An underwater somar source operating at a frequency of 60 khz directs its beam towards the surface the surface .if the velocity of sound in air is 330m/s,the wavelength and frequency of waves in air are
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Frequency of waves remains same, i.e. 60 Hz and wavelength
λ=v/n=330/60×10^3
= 5.5 mm.
λ=v/n=330/60×10^3
= 5.5 mm.
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