Question

An ungraduated thermometer of uniform bore is attached to a centimeter  scale and is found to read 10.3cm in melting ice  26.8cm in boiling water and 6.5cm in freezing mixture. Calculate the temperature of the freezing mixture. Please provide step by step answer​

Answer 1

Answer:

Calculate the temperature of the freezing mixture. ... Please let me know that is answer 23 degree centigrade or not. If this is the answer then I will post my solution.

Answer 2

Answer: The answer is -23.03 °C

Explanation: Firstly, let's note down whatever is given.

The ungraduated thermometer reads:

10.3 cm------ in melting ice (i.e 0°C)

26.8 cm------ in boiling water (i.e 100°C)

6.5 cm------ in an unknown freezing mixture (let's consider it's temperature to be x°C)

Here we have to find the x.

Now, the total length which the centimeter scale has from 0°C to 100°C will be:

(26.8-10.3) cm= 16.5 cm.

Therefore for 1 cm, the temperature will be (100-0)°C/16.5

Now, the difference of length between 0°C and freezing mixture=

(10.3-6.5) cm=3.8 cm.

So now, to find x, we have to multiple the difference of length which is (3.8), with the temperature of 1cm which is (100-0)°C/16.5.

So now:-

3.8 × (100-0)°C/16.5

=38/10 × 100 °C/16.5

=38/10 × 100×10/165 °C

=3800/165 °C =23.03 °C

Since the temperature x is less than 0°C so obviously the value will be negative.

Hence, x°C (the temperature of the freezing mixture) = -23.03°C

Here you go!