Question

An uniform meter scale weighting 200g holds weight of 10g,30g,50g,70g,90g at 10,30,50,70,90cm.Find the position of wedge on which scale has put.​

Answer 1

Answer:

As the scale is uniform, so the weight will be balanced at mid point i.e. 50 cm of the scale.

Let, M be the mass of the meter scale.

Using principle of moments, for equilibrium, sum of moment of force on left side of knife edge is equal to sum of moment of force on right side.

So, (70−50)Mg=(94−70)0.05g (as moment of force = force × perpendicular distance from fulcrum)

or M=0.06kg

Answer 2

Explanation:

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