An uniform rod of length 2L has mass per unit length m the moment of inertia after rod about an axis passing through its centre and perpendicular to its length is
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The moment of inertia of the rod is I = 2/3 m L^3.
Explanation:
Let the mass is dm, and the length is dx at a distance x from the given axis then
- dm = mdx
The moment of inertia of this mass will be
- dI = dmx^2 = mx^2dx
Thus, the moment of inertia of the half rod of length L
I = ∫L - 0 mx^2dx
I = mx^3/3
I = m L^3/ 3
The other half will also have this moment of inertia
Therefore, the moment of inertia of the rod
= 2 I
= 2 x m L^3/ 3 = 2/3 m L^3
Hence the moment of inertia of the rod is I = 2/3 m L^3.
Also learn more
What is the moment of inertia of a rod of mass M, length l about an axis perpendicular to it through one end?
https://brainly.in/question/1699512
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Explanation:
Physics 11th Rotational motion
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