Chemistry, asked by Alluarjun2303, 11 months ago

An unknown Aldehyde 'A' on reacting with alkali gives Beta-hydroxy-aldehyde, which loses water to from an unsaturated aldehyde, But-2-enal. Another aldehyde 'B' undergoes disproporational reaction in the presence of con.alkali to form products 'C' and 'D'. C is an aryl alcohol with the formula C7H8O.
i. Write the sequence of the reactions involved.
ii. Name the product, when 'B' reacts with Zinc amalgam and HCl.

Answers

Answered by topwriters
11

When B reacts with Zinc Amalgam and HCl, Toluene (C6H5CH3) is formed

Explanation:

Aldehyde compound A in reacting with alkali gives a β-hydroxy aldehyde which loses water to form unsaturated aldehyde but-2-enal. This is Aldol condensation reaction.

The aldehyde compound B undergo disproportion reaction with concentrated alkali. This is Cannizzaro's reaction.

Product C is an aryl alcohol with formula C7H8O. It must be C6H5CH2OH and formed by the condensation of benzaldehyde.

A is Ethanol - CH3CHO.

B is Benzaldehyde - C6H5CHO

Please refer to the attached picture for the sequence of reactions.

When B reacts with Zinc Amalgam and HCl, Toluene (C6H5CH3) is formed.

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