Question

An unknown gas having mass 8 gram is present in a container of 44.8 l. Find the gas and no. of atoms​

Answer 1

Answer:

8g has volume of 44.8 l

or

44.8l has 8g mass

1 l will have 8/44.8 g

then

22.4 l at stp will have mass of (8/ 44.8)*22.4 = 16g

molecular mass =16 hence the gas is oxygen and no. of atom 0.5 * 6.023* 10²³

Answer 2

Answer:

Helium and 12.04x10*23

Explanation:

if a gas has 2 moles then it contain 44.8L volume

mole=given mass/molar mass

2=8/molar mass

molar mass=8/2

molar mass=4g

element having 4g molar mass is Helium

no: of atoms=molex6.02x10*23

no: of atoms=2x6.02x10*23

no: of atoms=12.04x10*23