Question

an unknown metal was determined to have an atomic weight of 48.77g/mol and atomic radius of 0.1554nm. calculate the density of solid crystalline if it is HCP​

Answer 1

Explanation:

An unknown metal was determined to have an atomie weight of 48.77g/mol and an atomic radius of 0.1554nm. Calculate the density of solid crystalline if it is HCP.* The crystal structure of copper is found to be FCC. If two neighboring copper atoms are at a distance of 264 pm, find the edge length in nm and the volume of the unit cell in cubic em. A sample of a newly discovered crystalline substance weighs 14.56 grams and displaces 2.5ml of water. What is the density of the crystal? Find the atomic radius and density if it is a simple cubic cell? BCC? FCC? HCP?*

Answer 2

The density of solid crystalline if it is HCP​ will be 1.33×10⁻⁷g/cm³

Explanation:

Given Atomic weight of 48.77g/mol

Given Atomic radius of 0.1554nm.

Density of solid crystalline is to be determined

Density of the unit cell =mass of unit cell /volume of unit cell

Atomic radii l=2r given l=48.77

Volume =l³=(48.77)³

Density= 0.1554×10¹⁰÷(48.77×10²)³

1.33×10⁻⁷g/cm³

The density of solid crystalline if it is HCP​ will be 1.33×10⁻⁷g/cm³.