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An unknown polynomial yields a remainder of 2 upon division by x-1, and a remainder of 1 upon division by
X-2. If this polynomial is divided by (x - 1)(x-2), then the remainder is -
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hey mate here is ur answer
Please find below the solution to the asked query:
P ÷ (x – 1) remainder 2
P ÷ (x – 2) remainder 1
the difference in divisisor and remainder is
first case (x – 1) – 2 = (x – 3)
second case (x – 2) – 1 = (x – 3)
is same
so least polynomial is
(LCM of divisors) – difference
= (x – 1)(x – 2) – (x – 3)
= x^2 – 3x + 2 – x + 3
= (x^2 – 4x + 5)
so remainder when
(x^2 – 4x + 5) ÷ (x – 1)(x – 2)
= (x^2 – 4x + 5) ÷ (x^2 – 3x + 2)
quotient 1 and remainder
= (x^2 – 4x + 5) – (x^2 – 3x + 2)
= – x + 3
= 3 – x
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