Question

An unknown substance of molar mass 63 g mol' is
dissolved in water. If the solution has density
1.41 gmL-1 and mass percent of the solute is 63%
then molarity of the solution is​

Answer 1

Let, x=perecntage by mass=63%

d=density of the solution=1.41gmL^-1

m=molar mass of the given substance=63g

As we know that,

M=10dx/m

M=10X1.41X63/63 = 14.1M ans.

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