An unknown substance with a mass of 25 grams releases 550 joules of energy when undergoing a temperature increase of 10 degrees Celsius. What is the specific heat of that substance? Show your work
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Answer:
Explanation:
We Know That,
Q = m×C×∆T
Consider the substance as a solid so Cp = Cv
Given,. Q= 550 Joules, ∆T = 10℃, m= 25g
So, 550 = 25 × C × 10
C= 55/25
C= 2.2 Joule per gram Kelvin (J/GK)
Here Temperature is given in difference so Kelvin or ℃ can be used.
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