Question

an unloaded van has an acceleration of 5 ms-2 a fully loaded van weighs twice as much as the unloaded van . if the forward thrust on both vans is the same what is the acceleration of the fully loaded van​

Answer 1

AnswEr :

$\LARGE \underbrace{\frak{\: \: \: \: \; \; \; \; \; \; \: \: \: \; \; \; \: Given \: \: \; \; \; \; \; \; \: \: \: \: \: \; \; \; \:}}$

$\boxed{\begin{minipage}{4cm} {\underline{\textsf{\textbf{For Unloaded Van :}}}} \\ \\ \bullet {\sf{Acceleration (a_1) = 5ms^{-2}}} \\ \\ \bullet \sf{Force = F_1} \\ \\ \bullet \sf{Mass = m_1} \end{minipage}}\boxed{\begin{minipage}{4cm} {\underline{\textsf{\textbf{For loaded Van :}}}} \\ \\ \bullet {\sf{Acceleration = a_2}} \\ \\ \bullet \sf{Force = F_2} \\ \\ \bullet \sf{Mass (m_2) = 2m_1} \end{minipage}}$

• We're given F1 = F2

$\\ \\ \longrightarrow \tt{F_1\ =\ F_2} \\ \\ \\ \longrightarrow \tt{m_1 a_1\ =\ m_2\ a_2} \\ \\ \\ \longrightarrow \tt{\cancel{m_1}\ \times\ 5\ =\ 2\cancel{m_1}\ \times\ a_2} \\ \\ \\ \longrightarrow \tt{5\ =\ 2a_2} \\ \\ \\ \longrightarrow \tt{a_2\ =\ \dfrac{5}{2}} \\ \\ \\ \large \longrightarrow \underline{\boxed{\frak{a_2\ =\ 2.5\ ms^{-2}}}}$

Answer 2

Answer:

Explanation:

a=5

F=ma