An unmarked battery has an unknown internal resistance. If the battery is connected to a fresh 5.60-V battery (negligible internal resistance) positive to positive and negative to negative, the current through the circuit is 10.0 mA. If the polarity of the unknown battery is reversed, the current increases to 25.0 mA. Determine the source voltage and internal resistance of the un known battery. Assume that in each case the direction of the current is negative to positive in the 5.60-V battery.
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i don't kn ooo w
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bro Im class 7
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