Question

An unsaturated hydrocarbon on ozonolysis produces one molecule of methanal and one molecule of propanone. Identify the hydrocarbon and give IUPAC name.​

Answer 1

Explanation:

The scheme of reaction is

Compound(A)−→−−−−OzonolysisReductiveCH3−C∣Hethanal=O+O=C∣H−CH2−CH2−C∣H=O+O=C∣CH2−CH3Butane 1,4 dial propanonc

Thus , structure of A may be given as

H H CH3 | | ∣CH3−C=C−CH2−CH2−CH=C−CH→2-methyl octa-2, 6 diene8 7 6 5 4 3 2 1

The reactions involved in the question.

please make me as a brainliest.