An unstable nucleus contains 5 neutrons and 8 protons. It randomly emits three nucleons. What is the probability that 2 neutrons and proton are released?
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Answer:
40/143
Step-by-step explanation:
Choosing 2 neutrons from 5 = C(5,2) = 10
Choosing 1 proton from 8 protons = C(8,1) = 8
Choosing any 3 from 5 nuetrons and 8 protons = C(13,3) = 286
P(releasing 2 neutrons and a proton) = C(5,2) * C(8,1) / C(13,3)
= (10*8) / 286
= 40/143
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