Math, asked by butterflysly6, 12 days ago

: An unusual signpost indicates 8 cities with their distance from the signpost. These cities
are AGRA, JAIPUR, AJMER, DELHI, PANIPAT, ROPAR, AMBALA and BOMBAY. Each alphabet in the name of
cities is assign a numeric value, Total value of the letters in each city gives the corresponding distance. Signpost
indicates distance 186 km for AMBALA, 168 km for DELHI, 231 km for JAIPUR and 198 km for ROPAR while
other distances are missing.
29) What is the distance indicated for AJMER on the signpost?
(A) 205 km (B) 177 km (C) 138 km (D) None of these
30) For which of the following cities corresponding distance is maximum?
(A) BOMBAY (B) PANIPAT (C) AGRA (D) JAIPUR​

plz give answer

Answers

Answered by simikennady
50

Answer:

Take base value of A as x

For every increase in alphabet: +1

Therefore for AMBALA:

x + x+12 + x+1 + x + x+11 + x=186

6x + 24=186

Dividing By 6:

x + 4=31

x=27// (i.e. A=27)

For AJMER:

x + x+9 + x+12 + x+4 + x+17

= 5x + 42

= 135 + 42

= 177//

For PART 30, use the same substitution, don't need to calculate each completely just leave it at a (ax + b) form and compare.

Note; For the 5th alphabet, it's x+4, not x+5

Answered by shuklaaniket2007
3

Answer:

Ajmer distance will be 177 , by locating on alphabet series and taking x as a base

S

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