An uranium 235U fission reaction produces
216 MeV. The amount of 235U required to run a
100 MW nuclear power plant for a day with 100%
efficiency is
(1) 0.01 kg
(2) 1 kg
(3) 0.1 kg
(4) 0.001 kg
Answers
Answer:
0.0001kg
Explanation:
Energy released in 100MW nuclear power plant in a day with 100% efficiency=
100×10^6×24×60×60=86.4×10^11
Energy released by single uranium nucleus=216Mev=345.6×10^-13J
No. of uranium nuclei required=
86.4×10^11/345.6×10^-13=2.5×10^24
Mass of one uranium nucleus=235u=390.1×10^-27g
Mass of total no. of uranium nuclei=2.5×10^24×390.1×10^-27=0.0001kg
Thus the mass of uranium nuclei is 0.0001 kg
Option (4) is correct.
Explanation:
Given data:
- Isotope of uranium = 235 U
- Amount of energy produced = 216 MeV
- Capacity of power plant = 100 MW
- Efficiency = 100 %
Energy released by 100 MW = 100 × 10^6 × 24 × 60 × 60 = 86.4 × 10^11 J
Energy released by one uranium nucleus =216 Mev = 345.6 × 10^-13 J
No. of uranium nuclei required = 86.4 × 10^11 / 345.6 × 10^-13 = 2.5 × 10^24
Mass of one uranium nucleus = 235 u = 390.1×10^-27 g
Mass of total no. of uranium nuclei =2.5×10^24×390.1×10^-27 = 0.0001 kg
Thus the mass of uranium nuclei is 0.0001 kg