Question

An urn 'A'contains 2 white and 4 black balls. Another urn 'B'cont-
ains 5 white and 7 black balls. A ball is transferred from urn ‘A’ to
the urn 'B'. Then a ball is drawn from the urn B find the probability
that it will be white.
Lollo and​

Answer 1

Answer:

Step-by-step explanation:

P(A∣B)=P(A∩B)/P(B)

Here B=getting black ball, A= ball is from urn A

Hence, P(A∣B)=

2

1

​

×

(1/2×3/5+1/2×4/7)

5

3

​

​

=21/41

P(

A

∣B)=1−P(A∣B)

⇒P(

A

∣B)=1−P(A∣B) =1−21/40=20/41 please mark me as brainliest