an urn A contains 8 black balls and 5 white balls a second urn B contains 6 black and 7 white balls the probability that a blindfolded person in one draw shall obtain a white ball
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p(getting white ball)=5/13. in first urn
p( getting white balls)=7/13. in second urn
p( getting white balls)=7/13. in second urn
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Answer:
P(for urn A)=5\13
P(for urn B)=7\13
Total P(for white ball)=12\26
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