Question

An urn contains 10 black and 5 White balls. Two balls are drawn from the urn one afier other without replacement. What is the probability that both the balls drawn are black?

Answer 1

Answer:

$\frac{9}{35}$

Step-by-step explanation:

An urn contains 10 black and 5 White balls.

Total balls n(S)= 15

Probability of drawing one black ball from the urn

P(B)=

$\frac{10}{15} \\ \\ = \frac{2}{3}$

Probability of drawing another black ball if one black ball is already choosen:

P(B1|B)

$= \frac{9}{14}$

The probability that both the balls drawn are black:P(BB)

$\frac{2}{5} \times \frac{9}{14} \\ \\ = \frac{9}{35}$

Hope it helps you.