An urn contains 10 black and 5 white balls. Two balls are drawn from the urn one after the other without replacement. What is the probability that both drawn balls are black?
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Answer:
Step-by-step explanation:
Solution
verified
Let B(i=1,2) denote the event of getting a back ball in the i
th
draw.
Required probability =P(B
1
∩B
2
)=P(B
1
)P(B
2
/B
1
)
=
15
10
×
14
9
=
7
3
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