Question

an urn contains 10 red and 3 black balls.another urn contains 3 red and 5 black balls. Two balls are transferred from the first urn to the second urn without noticing their color. One ball is now drawn from the second urn and it is found to be red. What is the probability that 1 red and 1 black are transferred

Answer 1

$\huge \bf{ \red{answer}}$


$\bf{question - }$

An urn contains 10 red and 3 black balls.another urn contains 3 red and 5 black balls. Two balls are transferred from the first urn to the second urn without noticing their color. One ball is now drawn from the second urn and it is found to be red. What is the probability that 1 red and 1 black are transferred

$\bf{step \: by \: step \: explanation}$
Total number of balls in 1st urn

= 10+3

= 13

Now

Total number of balls in 2nd urn

= 3+5
= 8

According to question

2 balls are transferred from 1st urn to 2nd



Probability of event= no of possible outcomes/total number of outcomes


probability of transferring 2 red ball

= 10/13...........(1)



and

probability of transferring 2 black balls

= 3/13...........(2)


hence

from equation 1 and 2.

10/13-3/13

=>. 10-3/13

=> 7/13

$\huge \mathfrak{ \orange{thanks}}$

Answer 2

Please see the attachment