Math, asked by BrainlyHelper, 1 year ago

An urn contains 10 red and 8 white balls. One ball is drawn at random. Find the probability that the ball drawn is white.

Answers

Answered by nikitasingh79
97

SOLUTION :  

GIVEN : Number of red balls = 10

Number of white balls = 8  

Total number of balls in an urn = 10 + 8= 18

Total number of outcomes = 18

Let E = Event of selecting a white ball  

Number of outcome favourable to E = 8

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 8/18 = 4/9

Hence, the required probability of getting a white ball , P(E) = 4/9 .

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Answered by neerajmodgil85pc43rj
51
No. of white balls = 8
No. of red balls = 10
Total = 10+8
= 18
Probability = 8/18
= 4/9
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