Math, asked by viduola, 1 year ago

an urn contains 12 white balls and 8 black balls. one ball is drawn at random. what is the probability that the ball is
A) white
B) black

Answers

Answered by rafiaibrahim903
0

Answer:

The required answer is A) white=0.6

B) black=0.4

Step-by-step explanation:

Probability: The probability that an event will occur, such as rolling a two on the die or drawing a king from a deck of cards, is known by the mathematical word probability.

Given: white balls=12 and black balls=8

Total balls=12+8=20

Based on the given condition,.

Probability of white ball=12/20=3/5=0.6

Probability of black ball=8/20=2/5=0.4

Therefore,  the probability of the balls

A) white=0.6

B) black=0.4

#SPJ3

Answered by prateekmishra16sl
3

Answer: Probability of drawing white ball is 3/5 and probability of drawing black ball is 2/5

Step-by-step explanation:

Probability  = Favourable outcomes ÷ Total outcomes

Number of white balls in urn = 12

Number of red balls in urn = 8

Total number of balls = 12 + 8 =20

A) Probability of drawing white ball = Number of white balls ÷ Total number of balls

Probability of drawing white ball  =   \frac{12}{20} = \frac{3}{5}

B) Probability of drawing black ball = Number of black balls ÷ Total number of balls

Probability of drawing black ball  =   \frac{8}{20} = \frac{2}{5}

#SPJ1

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