an URN contains 4 red and 6 green balls another URN contains 2 red and 5 green balls and URN was selected at random and then a ball was drawn from it if it was found to be Red then the probability that it has been drawn from the first URN is
Answers
Answered by
3
Answer:
from first URN
Step-by-step explanation:
favorable event= 4
Total event = 10
Answered by
4
Answer:
7/12
Step-by-step explanation:
1st: Ball is drawn from 1st urn
R: Drawn ball is red
P(1st/R)= P(1st∩R)/P(R)=( 4/10*1/2) / (1/2*4/10+1/2*2/7) = 1/5 / (1/5+1/7) = 7/12
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