Question

An urn contains 5 blue and 4 black balls if three balls are drawn at random what is the probability that two are blue and ones black

Answer 1

the ans is 5/9×4/8×4/7

Answer 2

Answer:

The probability that two are blue and ones black is

$\frac{10}{21}$

Step-by-step explanation:

Given : An urn contains 5 blue and 4 black balls if three balls are drawn at random.

To find : What is the probability that two are blue and ones black?

Solution :

Number of Blue Balls=5

Number of Black Balls=4

The number of way of getting two blue balls from 5 ball is $^5C_2$

The number of way of getting one black balls from 4 ball is $^4C_1$

Total number of way  getting 3 balls from 9 is $^9C_3$

The probability that two are blue and ones black is

$P=\frac{^4C_1\times ^5C_2}{^9C_3}$

$P=\frac{4\times 10}{84}$

$P=\frac{40}{84}$

$P=\frac{10}{21}$

Therefore, The probability that two are blue and ones black is

$\frac{10}{21}$