Question

An urn contains 5 white and 3 black balls. Two balls are drawn at random
without replacement. If X denotes the number of white balls, then find the
probability distribution of X​

Answer 1

• step by step answer...
• best of luck for your work hope you like it ..have a good day

Answer 2

X = $\frac{5}{8}$.

• Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.
• Probability can range from 0 to 1, with 0 denoting an impossibility and 1 denoting a certainty. For pupils in Class 10, probability is a crucial subject because it teaches all the fundamental ideas of the subject. One is the probability of every event in a sample space.

Here, according to the problem, there are 5 white and 3 black balls.

If 2 balls are drawn at random, the first case can be that one ball is white and another ball is black or the second case can be is that both balls are white.

Then, the probability for the first case is,

$\frac{5C_{1} }{8C_{1} } .\frac{3C_{1} }{7C_{1} }\\=\frac{15}{56}$

Also, for the second case, we have,

$\frac{5C_{1} }{8C_{1} } .\frac{4C_{1} }{7C_{1} }\\=\frac{20}{56}$

Then, X = Sum of probabilities in both cases = $\frac{5}{8}$.

Hence, X = $\frac{5}{8}$.

Learn more here

https://brainly.in/question/1350976

#SPJ9