An urn contains 5red and 7 green balls.a ball is drawn at random and its colour is noted.the ball is placed back into the urn along with another vall of same colour.tje probability of getting a red vall in the next draw is
Answers
Given,
red balls=5
green balls=7
therefore,n(s)=12
Now,
The probability of getting a red ball in the next draw
i.e, n(E)=number of red balls by total number of balls
=5/12
5/12 is the probability of getting a red ball in the next draw
Step-by-step explanation:
An urn contains 5red and 7 green balls
=> Red balls = 5
Green Balls = 7
Total Balls = 12
There are two cases that in first Draw either Red or green Ball is drawn
Case 1 : Red ball is Drawn
Probability = 5/12
Now this red ball & addition red ball has been placed Back
so Urn has now 6 Red Balls & 7 Green Balls
Probability of Red Ball = 6/13
Probability = (5/12)(6/13) = 30/156
Case 2 Green ball is Drawn
Probability = 7/12
Now this green ball & addition green ball has been placed Back
so Urn has now 5 Red Balls & 8 Green Balls
Probability of Red Ball = 5/13
Probability = (7/12)(5/13) = 35/156
probability of getting a red ball in the next draw is 30/156 + 35/156
= 65/156
= 5/12
Learn more:
There are two urns. the first urn contains 3 red and 5 white balls ...
https://brainly.in/question/13404745
An urn contains 6 yellow, 5 blue and 2 white marbles. If three ...
https://brainly.in/question/11611584
Two balls are drawn from an urn containing 5 green, 3 blue, 7 yellow ...
https://brainly.in/question/7795905