Question

an urn contains 6 red and 4 blue balls.two balls are drawn at random with replacement.find the probability of getting a)2 red balls b)2 blue balls c)one red and one blue ball

Answer 1

Answer:

a) 0.36

b) 0.16

c) 0.48

Step-by-step explanation:

It is given that:

• There are 6 red balls, and 4 blue balls
• The balls are drawn randomly WITH replacement

Therefore, the total amount of balls is always 10.

a) P (2 red) = P(Red) * P(Red)

P(2 red) = $\frac{6}{10}* \frac{6}{10}=0.36$.

b) P (2 blue) = P(Blue) * P(Blue)

P(2 red) = $\frac{4}{10}* \frac{4}{10}=0.16$.

c) P(1 red and 1 blue) = 1 - P(2 red) - P(2 blue)

P(1 red and 1 blue) = 1 - 0.36 - 0.16 = 0.48.