An urn contains 6 yellow, 5 blue and 2 white marbles. If three marbles are picked at random, what is the probability that at least one is blue?
a)115/199
b)115/143
c)28/197
d)28/143
Answers
Answered by
14
Answer:
115/143
Step-by-step explanation:
An urn contains 6 yellow, 5 blue and 2 white marbles. If three marbles are picked at random, what is the probability that at least one is blue?
a)115/199
b)115/143
c)28/197
d)28/143
We will find out probability of no blue balls
and reduce it from 1 to get the probability that at least one is blue
Probability of no blue balls :
Total Balls 13 , non-Blue Balls = 8
After selecting 1st non-blue ball Total Balls 12 , non-Blue Balls = 7
in last selection Total Balls 11 , non-Blue Balls = 6
Probability of no blue balls : = (8/13)(7/12)(6/11)
= 8 * 7 * 6 /( 13 * 12 * 11)
= 28/143
the probability that at least one is blue = 1 - 28/143
= 115/143
Answered by
0
Answer:
115/143
Step-by-step explanation:
is the ans for about question
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