An urn contains 7 white and 3 red balls. Two balls are drawn together, at random from this urn. Compute the expected number of white balls drawn
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Answer:
probability of neither of them is white= 3/10
probability of getting white ball= 7/10
hope it helps
Step-by-step explanation:
see the concept is no. of particular balls upon total no of balls
total no of balls = 7 + 3 = 10
according to this u can do this type of question
hope it helps
.......................xd
pls mark it as brainliest sister
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