an urn contains 7 white balls and 3 red balls. two balls are drawn together at random from this urn. compute probability that neither of them is white. hence compute the expeted number of white balls drawn
Answers
probability of getting white ball= 7/10
1.4 is expected number of white balls drawn
0.09 is the probability that neither of them is white
Step-by-step explanation:
an urn contains 7 white balls and 3 red balls
Total Balls = 7 + 3 = 10
Probability of White = 7/10 = 0.7
Probability of Red = 3/10 = 0.3
Probability of not white = 0.3
two balls are drawn together at random from this urn.
Neither White = 0 White
P(0) =²C₀(0.7)⁰(0.3)² = 0.09
P(1) =²C₁(0.7)¹(0.3)¹ = 0.42
P(2) =²C₂(0.7)²(0.3)⁰ = 0.49
0.09 is the probability that neither of them is white
expected number of white balls drawn = 0 * P(0) + 1 * P(1) + 2 * P(2)
= 0 + 0.42 + 0.98
= 1.4
1.4 is expected number of white balls drawn
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