An urn contains 7 white balls and 4 red balls. Draw three balls from the urn without replacement. What us the probability that the first ball is read, the second white, and the third red?
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Total balls = 7+4 = 13;
probability of Selecting first ball red = 4/13;
probability of Selecting seconds ball White = 7/12;
probability of Selecting third ball red ball = 3/ 11;
Total value of probability for given condition is = (4*7*3)/(13*12*11)
= 7/143
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