Question

an urn contains 8 white balls and 12 black balls.find the probability of drawing two successive white balls without replacement​

Answer 1

Answer:

There are total 13 balls out of which 8 are red and 5 are white.

Favourable case of first draw is to get 3 white balls out of 5 white balls.

Probability P1 = 5C3/13C3

If this hapoens then remainings are - 2 white balls and 8 red balls.

Favourable case is to get 3 red balls out of 8 balls.

Probability P2 = 8C3/10C3

Both the events are independent of each other, hence total probability is P1*P2 = (5C3 * 8C3)/(13C3 * 10C3)

Hope it helps!

Step-by-step explanation: