Question

An urn contains 8white and 3red balls. If two balls are drawn at random,find the probability that both are white and both are red

Answer 1

Answer:

Here you have to consider two different events - the probability that you choose a white ball first and then a red and the probability that you choose a red ball first and then a white ball. We compute each individually

P(white then red) = 8/11 * 3/10

P(red then white) = 3/11 * 8/10

Since these are independent we sum them up to get the total probability:

2*(8/11 * 3/10) = 48/110 = 24/55 = 44%

Thus you have the probability that one is of each color.

Hope u r clr with this :)

Answer 2

Answer:

44%

Step-by-step explanation:

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