Question

An urn contains 9 balls containing 2 white,
3 blue & 4 black balls. Three balls are drawn
from urn with replacement find the probability
that
all balls are of different colours​

Answer 1

A urn has 3 are red,4 are blue and 2 are green

event of choosing 3 balls

n(S)=

9

C

3

event of choosing 3 different colour balls

n(E)=

3

C

1

×

4

C

1

×

2

C

1

Probability =

9

C

3

3×4×2

=

9!

24×3!

×6!=

9×8×7

24×6

=

7

2

.

Answer 2

Given : 2 white + 3 blue+ 4 black = 9 balls

To find : probablity of three diffrent balls

Answer : 8/243

Step-by-step explanation:

question of with replacenemt so find probablity of each ball one after one...

1. p(a) = 2/9 ( chose white ball )
2. p(b)= 3/9 ( chose blue ball )
3. p(c) = 4/9 ( chose black ball )

multiple of all possiblity is your ans..

2×3×4/ 9×9×9 = 8/243

please like ans..