Question

An Urn contains two white marbles and one black marble. A marble is drawn from the Urn without replacement and put aside without my seeing it. Then a second marble is drawn, and it is white.
What is the probability that the unknown removed marble is white, and what is the probability that it is black?

Answer 1

Step-by-step explanation:

probability of white marble = 1/3

probability of white marble = 1/3probability of black marble = 1/3

Answer 2

The given question is

An Urn contains two white marbles and one black marble. Then the total number of marbles is 3.

The total sample space is n(s) =3

A marble is drawn from the Urn without replacement and put aside without my seeing it.

Then a second marble is drawn, and it is white.

What is the probability that the unknown removed marble is white, and what is the probability that it is black?

If a first marble drawn is white means the probability is

p(w) =possibility of getting a white marble / total number of marble

$p(w) = \frac{n(w)}{n(s)} = \frac{2}{3}$

p(b) = possibility of getting a black marble /total number of marble.

$p(b) = \frac{n(b)}{n(s)} = \frac{1}{3}$

#spj2

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