Question

An X-ray tube operates at 40 kV. Suppose the electron converts 70% of its energy into a photon at each collision. Find the lowest there wavelengths emitted from the tube. Neglect the energy imparted to the atom with which the electron collides.

Answer 1

Answer:

An X ray tube operates at 40 kV

here V = 40 kV

so V = 40 × 10 ^3 V

our energy is 40 × 10 ^3eV

The electron converts 70 percent of its energy

So Energy = 70 percent

Energy = 70/100 × 40 × 10^3

= 28 × 10 ^3

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wave length given by .. (first wavelength)

formula..

wave length = hc / E

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then see the attachment (in copy )

This is your answer..

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