Anagha’s mother bought an equal number of ladoos and pedas. She put 13 1/3 of ladoos and 15 1/5 of pedas into a packet and gave it to Anagha to distribute at school. If there were a total of 80 sweets in the packet, how many ladoos did Anagha’s mother buy?
Answers
Given :-
- Anagha’s mother bought an equal number of ladoos and pedas.
- She put 1/3 of ladoos and 1/5 of pedas into a packet and gave it to Anagha to distribute at school.
- There were a total of 80 sweets in the packet.
To Find :-
- How many ladoos did Anagha’s mother buy ?
Solution :-
Let us assume that, Anagha's mother bought total x ladoos and x pedas . { Equal number of both .}
given that, She put 1/3 of ladoos and 1/5 of pedas into a packet .
So,
→ Ladoos she put in packet = (1/3) of x = (x/3) ladoos.
→ Pedas she put in packet = (1/5) of x = (x/5) pedas.
Than,
→ Total sweets in packet was = (x/3) ladoos + (x/5) pedas = (x/3) + (x/5) = (5x + 3x)/15 = (8x/15)
given that, There were a total of 80 sweets in the packet.
Therefore,
→ (8x/15) = 80
→ 8x = 80 * 15
dividing both sides by 8,
→ x = 10 * 15
→ x = 150 . (Ans.)
Hence, Anagha’s mother buy 150 Ladoos ..
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Answer:
Given :-
Anagha’s mother bought an equal number of ladoos and pedas.
She put 1/3 of ladoos and 1/5 of pedas into a packet and gave it to Anagha to distribute at school.
There were a total of 80 sweets in the packet.
To Find :-
How many ladoos did Anagha’s mother buy ?
Solution :-
Let us assume that, Anagha's mother bought total x ladoos and x pedas . { Equal number of both .}
given that, She put 1/3 of ladoos and 1/5 of pedas into a packet .
So,
→ Ladoos she put in packet = (1/3) of x = (x/3) ladoos.
→ Pedas she put in packet = (1/5) of x = (x/5) pedas.
Than,
→ Total sweets in packet was = (x/3) ladoos + (x/5) pedas = (x/3) + (x/5) = (5x + 3x)/15 = (8x/15)
given that, There were a total of 80 sweets in the packet.
Therefore,
→ (8x/15) = 80
→ 8x = 80 * 15
dividing both sides by 8,
→ x = 10 * 15
→ x = 150 . (Ans.)
Hence, Anagha’s mother buy 150 Ladoos ..