Physics, asked by snehachavan26, 2 months ago

Analyse the circuit to answer the following questions:
a) What type of combinations are the lamps arranged in ?
60V
b) With reference to the above answer explain the advantages
of this combination(any two)
ЗА
5A
А
B
4A
ЗА
c) Explain with proper calulations which lamp glows the
brightest
d) Find out the total resistance of the circuit.​

Answers

Answered by pratham7777775
0

Answer:

.

As the three bulbs are connected in parallel, the voltage applied across them would be the same, lets say its V.Now, due to the fact that the power dissipated by the three bulbs is different the current flowing through them would be different and thus they will have different brightness.Now, the brightness of a bulb is directly proportional to the power it uses or the amount of current it draws. Thus, in this case the brightness of bulb B (60 W) will be more than that of the bulb A (40 W) but less than that of the bulb C (100 W). That is, C has the maximum brightness and the bulb has has the least brightness. Bulb B in between.

Answered by Zodiacdragon298
0

Explanation:

As the three bulbs are connected in parallel, the voltage applied across them would be the same, lets say its V. Now, due to the fact that the power dissipated by the three bulbs is different the current flowing through them would be different and thus they will have different brightness. Now, the brightness of a bulb is directly proportional to the power it uses or the amount of current it draws. Thus, in this case the brightness of bulb B (60 W) will be more than that of the bulb A (40 W) but less than that of the bulb C (100 W). That is, C has the maximum brightness and the bulb has has the least brightness. Bulb B in between.

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