Analyse the given circuit diagram and answer the following questions.
1. What will be the electric current through the resistance A?
2. What will be the electric current through the resistance B ?
3. What will be the ammeter reading?
4. How should be the resistance wire be arranged to reduce the ammeter reading ?
Answers
Answer:
Current Through A= 4 ampere, Current Through B= 2 Ampere, Ameter Reading= 6 Ampere.The Resistance should be arranged in series to reduce the ameter reading.
Explanation:
The Net Resistance of the Circuit R=1/(1/6+1/3) (I directly simplified it)
= 1/(1/2)
=2 ohm
Net Current=12/2=6 Amp (Ameter Reading)
Current through A= [6/(3+6)]*6
=4 Amp
Current Through B=[3/(3+6)]*6
=2 Amp
Hope this Helps:)
Given:
A circuit diagram with two resistors A and B and a 12 volts battery
To Find:
1. The electric current through resistance A?
2. The electric current through resistance B?
3. The ammeter reading?
4. How should be the resistance wire be arranged to reduce the ammeter reading?
Solution:
From the diagram, we can infer that both A and B are attached in parallel.
⇒ They have the same voltages across them, which is 12V
1. Using Ohm's law, the electric current around resistor A = V/R = 12/3 = 4A
2. Again using Ohm's law, the electric current around resistor B = 12/6 = 2A.
3. The ammeter shows the current in the branch it is connected to. Here, it shows the net current flowing through the battery.
I = V/Req
Here, req is the equivalent resistance of the parallel combination.
Using the formula, Req = AB/A+B = 18/9 = 2Ω
Substituting,
The ammeter reading = I = 12/2 = 6A
4. To reduce the ammeter reading, the Req of the circuit should be increased. Since we know that when two resistors are connected in series, the equivalent resistance is greater than either of the resistances,
⇒ A and B should be arranged in series to reduce the ammeter reading.