Question

Analyse the given samples. (Symbols are not real) i) P-22.4 L NH3 at STP ii) Q - 128g SO2 iii) R - 117g Nacl iv) S -22g CO2 (Hint: GMM NH3 =17g, CO2 = 44g, Nacl = 58.5g SO2 - 64g] Find the number of molecules in Q.find q
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Answer 1

Answer:

Given: Mass of ammonia at STP = 170g

Molecular mass of NH³ = 17g

First, we will calculate the number of moles by applying the formula given:

$number \ of \ molecules \ = \frac{mass \: of \: {nh}^{3} }{gram \: moleculer \: mass \: of \: {nh}^{3} }$

number of moles = 170g/170g

Number of moles = 10

Thus, number of moles of CaCO³ is 10

Now 1 mole of any gas occupies 22.4 litres of volume.

∴ 1 mole of NH³ = 22.4 litre

10 moles of NH³ = 22.4 × 10 = 224 litres

Thus, the volume occupied by 170g of NH3 is 224 litres.