Analysing Distance Alia and Shagun are friends living on the same street in Patel Nagar. Shagun's house is at the intersection of one street with another street on which there is a A library. They both study in the same school and that is not far from Shagun's house. B C Suppose the school is situated at the point 0, i.e., the origin, Alia's house is at A. Shagun's house is at E Based on the above information, answer the following questions. library is at C. O (i) How far is Alia's house from Shagun's house? (a) 3 units (b) 4 units (c) 5 units (d) 2 units it) How far is the library from Shagun's house? (a) 3 units (b) 2 units (c) 5 units (d) 4 units (iii) How far is the library from Alia's house? (a) 2 units (b) 3 units (c) 4 units (d) None of these (iv) Which of the following is true? (a) ABC forms a scalene triangle (c) ABCforms an equilateral triangle (b) ABC forms an isosceles triangle (d) None of these (v) How far is the school from Alia's house than Shagun's house? (a) v13 units (b) v5 units (c)(13+5) units (d) (V13-v5) units maths.
Answers
Given: Suppose the school is situated at the point 0, i.e., the origin, Alia's house is at A. Shagun's house is at B library is at C.
To Find: How far is Alia's house from Shagun's house?
How far is the library from Shagun's house?
How far is the library from Alia's house?
How far is the school from Alia's house than Shagun's house?
Solution:
Alia's house is at A. ( 2 , 3)
Shagun's house is at B ( 2 , 1)
library is at C ( 4 , 1)
school is situated at the origin (0 , 0)
Alia's house from Shagun's house =√(2 - 2)² + (1 - 3)² = 2 units
library from Shagun's house = √(4- 2)² + (1 - 1)² = 2 units
library from Alia's house = √(4- 2)² + (1 - 3)² = 2√2 units
none of the given option
ABC forms an isosceles triangle as AB = BC = 2
school from Alia's house = √13
school from Shagun's house = √5
√13 - √5 far is the school from Alia's house than Shagun's house
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