Question

analysis of a sample of iron oxide shows that it has the formula Fe0.90 O. the fraction of iron present as Fe2+ will be about ​

Answer 1

Explanation:

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Answer 2

Answer:

Let's assume that there are x molecule fraction of Fe

+2

& 0.93−x molecular fraction of Fe

+3

.

Now, using charge conservation formula for Fe

0.96

O

1.00

, we get

⇒x(+2)+(0.99−x)(+3)−2=0

⇒2x−3x+2.79−2=0

⇒x=0.79

Fraction of Fe

+2

=0.79 & frcation of Fe

+3

=0.14

Percentage of Fe

+2

=

0.93

0.79

×100=84.9%

Percentage of Fe

+3

=

0.93

0.14

×100=15.05%