Question

Anand earns Rs. 80 in 7 hours and Pramod earns Rs. 90 in 12 hours. The ratio of their earning? How to solve this?

Answer 1

Anand earns Rs 80 in 7 hours

⇒ 1 hour = Rs 80/7

Pramod earns Rs 90 in 12 hours

⇒ i hour = 90/12 = Rs 15/2

Form ratio:

Ratio of Anand : Pramod = 80/7 : 15/2

Multiply both side by 7 :

Ratio of Anand : Pramod = 80 : 105/2

Multiply both sides by 2:

Ratio of Anand : Pramod = 160 : 105

Simplify:

Ratio of Anand : Pramod = 160 ÷ 5: 105 ÷ 5

Ratio of Anand : Pramod = 32 : 21

Answer: The ratio is 32 : 21

Answer 2

Hey there !

Solution:

Anand case:

Rs 80 : 7 hours :: Rs x : 1 hour

Product of means = Product of extremes

=> 7 × x = 80 × 1

=> x = 80 / 7

Therefore for 1 hour, Anand earns Rs. 80 / 7

Pramod's Case:

Rs 90 : 12 hours :: Rs y : 1 hour

Product of means = Product of extremes

=> 90 × 1 = 12 × y

=> y = 90 / 12

Therefore for 1 hour Pramod earns Rs. 90 / 12

Now we have to find ration between Anand and Pramod's Salaries. Hence we have to get x : y = ?

Solving this further we get,

x : y = $\frac{ 80}{7} : \frac{90}{12}$

=> $\frac{x}{y} = \frac{ \frac{80}{7} }{ \frac{ 90}{12} }$

=> $\frac{x}{y} = \frac{80}{7}\times \frac {12}{90}$

=> $\frac{x}{y} = \frac{960}{630} \\ \\ Dividing \hspace{1mm} by \hspace{1mm} 30 \hspace{1mm} we \hspace{1mm} get, \\\\ \frac{x}{y} = \frac{32}{21}$

Hence the ratio of salaries are x : y = 32 : 21.

Hope my answer helped !