Anand has won 80% of the games he has played so far in tournaments his goal is to win 90% of all the games he has to play in the tournament if he has already played 15 out of the total 50games that he has to play what is the maximum number of games he can afford to loose in the remaining games and yet meet his goal?
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Solution:-
Total games to be played by Anand = 50
Games played = 15
Winning percentage = 80 %
Games won = (15*80)/100 = 12 games
Remaining games to be played = 50 - 15 = 35 games
His goal is to win 90 % of all the games.
So, 90 % of 50
= (50*90)/100 = 45 games
He will have to win 45 games out of 50 games so that his winning percentage will be 90 %.
Games already won = 12 games
Total games to be won = 45 games
Games yet to be won so that his goal to win 90 % of all the games is achieved = 45 - 12 = 33 games
The maximum number of games he can afford to loose = 35 - 33
= 2 games
So, he can afford to loose only 2 games.
Answer.
Total games to be played by Anand = 50
Games played = 15
Winning percentage = 80 %
Games won = (15*80)/100 = 12 games
Remaining games to be played = 50 - 15 = 35 games
His goal is to win 90 % of all the games.
So, 90 % of 50
= (50*90)/100 = 45 games
He will have to win 45 games out of 50 games so that his winning percentage will be 90 %.
Games already won = 12 games
Total games to be won = 45 games
Games yet to be won so that his goal to win 90 % of all the games is achieved = 45 - 12 = 33 games
The maximum number of games he can afford to loose = 35 - 33
= 2 games
So, he can afford to loose only 2 games.
Answer.
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