anand is five years older than his sister anju . their father is 20 years older than anand . four years ago , the father's age was twice the sum of ages of anand and anju then. find their present ages.
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Answers
Answer:
Anand = 14 Years
Anju= 9 years
Anand's father = 34
Step-by-step explanation:
1st we need t0 find the age of anju
let anju = x
Anand= A
His father is = F
A = 5+X
His father= 20+(5+x) = 25+x
4years ago His father's age was twice the sum of anand and anju's age
Well
(25+x)-4 = 2( A-4)+(X-4)
as we know A= 5+x
by putting A values
21+ x = 2((5+x-4)+(x-4))
21+x = 2(1+x+x-4)
21+ x = 2( 2x -3)
21+ x = 4x-6
21 +6 = 4x-x
3x = 27
x = 27/3
x = 9
Now we know that anju's age is 9 year
well
Anand = 5+9 = 14
anand's father = 20+14 = 34
Verify :
Anand 5 years older then his sister: 9+ 5= 14 anands age
Anand's father 20 year older then anand: 20+14anands age= 34 Years
4 years ago anands father's age was twice the sum of anand and anju's age
34-4years ago = 2(Anands age 14-4years ago+ Anju's age 9- 4years ago)
30= 2(10+5)
30= 30
it proves that
their present ages are
Anand = 14
Anju= 9
anand's father = 34
Hope its clear
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