Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time?
Answers
Answered by
49
Time(t)=30 min=1/2 hr
Total Distance(D)=2km
Speed for 1st km=3km/hr
Since, D=S*t
1 km=3*t
Therefore, t=1/3 hr
So, remaining time=1/2 hr - 1/3 hr
=1/6 hr
Remaining distance=1 km
Therefore, Speed required=D/t
=1*6/1
=6 km/hr
Total Distance(D)=2km
Speed for 1st km=3km/hr
Since, D=S*t
1 km=3*t
Therefore, t=1/3 hr
So, remaining time=1/2 hr - 1/3 hr
=1/6 hr
Remaining distance=1 km
Therefore, Speed required=D/t
=1*6/1
=6 km/hr
Answered by
3
Answer:
Explanation:
A-----------B-----------C
let A is anand house
B is1km distance apart from his house
C is school
we know time =distance/speed
tAB=1/3 hour
tAB is time takenfrom A to B
tBC=1/2-1/3 =1/6hour
so, speed=distance/time=1/(1/6)=6km/h
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