Math, asked by 19sunil20pbppi7, 30 days ago

Ananya is three years elder than Diksha. Six years ago, Ananya's age was four times Diksha's age.
Find the ages of Ananya and Diksha.​

Answers

Answered by keerthivardhaneswar
1

Answer:

Ananya's age is 10 years,

Diksha's age is 7 years.

Step-by-step explanation:

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Answered by bd21454
7

Step-by-step explanation:

Let,

Ananya's age = X

Diksha's age = Y

1st problem,

(X-Y)=3

or, X= Y+3

6 years ago ,

Ananya's age = (X-6)

Diksha's age = (Y-6)

2nd problem ,

(X-6)= 4×(Y-6)

or, X= 4Y-24+6

or, X= 4Y-18

from 1st and 2nd problem Compare the value of X

Y+3=4Y-18

or , Y-4Y= -18-3

or, -3Y= -21

or, Y= 21/3

or, Y= 7

therefore, Diksha's age is= 7 years

Ananya's age is =

X=Y+3( from the 1st prblm)

or, X= 7+3 ( Put the value of Y)

or, X= 10

Ans- Ananya's age= 10 years

Ananya's age= 10 yearsDiksha's age= 7 years

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