Question

Anar substance and angle of 90 degree at the centre of circle of radius 14 cm write the area of minor sector thus form in terms of pi

Answer 1

Question:

An arc subtends an angle of 90 degree at the centre of circle of radius 14 cm write the area of minor sector thus form in terms of pi.

Answer:

49π cm²

Step-by-step explanation:

Find the area of the circle:

Area of a circle = πr²

Area of the circle = π(14)² = 196π cm²

Find the area of the sector:

Area of a sector = θ/360 x Area of the circle

Area of the sector = 90/360 x 196π

Area of the sector = 49π cm²

Answer: Area of the sector = 49π cm²

Answer 2

Answer:

The area of the minor sector will be $49\pi cm^2$.

Step-by-step explanation:

In context to the question asked,

We have to find the area of the minor sector in terms of $\pi$,

As per data given in the question,

We have,

$r = 14cm$

$\theta = 90 ^\circ$

Now, we will find the area of the minor sector:

The formula to be used:-

Area of the minor sector -

$=> \frac{\theta}{360} \times \pi r^2$

Substituting the given values,

$=> \frac{90}{360} \times \pi \times (14)^2$       $...( 1)$

Now, by simplifying the equation ( 1 ):

$=> \frac{1}{4} \times \pi \times (14)^2$

$=> \frac{1}{4} \times \pi \times 14\times 14$

$=> \pi \times 7 \times 7$

$=> 49\pi$

Therefore, the area of the minor sector will be $49\pi cm^2$.