Question

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11. Diagram of the adjacent picture frame has outer dimensions 24 cm 28 cm
and inner dimensions 16 cm 20 cm. Find the area of each section of the frame. the
width of each section is same​

Answer 1

Answer:

Mensuration:

Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.

Plane Figure: A figure which lies in a plane is called a plane figure.

For e.g:  a rectangle, square, a rhombus, a parallelogram, a trapezium.

 

Perimeter:

The perimeter of a closed plane figure is the total length of its boundary.

In case of a triangle or a polygon the perimeter is  the sum of the length of its sides.

Unit of perimeter is a centimetre  (cm), metre(m) kilometre(km) e.t.c

Area: The area of the plane figure is the measure of the surface enclose by its boundary.

 

The area of a triangle are a polygon is the measure of the surface enclosed by its sides.

A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.

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Solution:

In Figure (I) and (II) are similar in dimensions & also figures (III) and (IV) are similar in dimensions.

 

Width is 28- 24= 4 cm

Width is same of each section.

Width is height of all the trapezium.

Area of figure (I) = Area of trapezium

= ½(sum of parallel sides) ( height)

= ½ (28+20)(4)

= ½( 48)(4)

= 48×2

= 96 cm²

Area of figure (II) = 96 cm²

Area of figure (I) = Area of figure (II) = 96 cm²

 

 

 

Area of figure (III)

= Area of trapezium =  ½(sum of parallel sides) ( height)

= ½(24+16)(4)

= ½(40)(4)

= 40× 2

= 80 cm²

Area of figure (IV) = 80 cm²

Area of figure (III) = Area of figure (IV) = 80 cm²

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Hope this will help you...

Step-by-step explanation: